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Anarel [89]
2 years ago
11

#3) A skier is at the top of his hill ready to ski down. The skier is now located at

Mathematics
1 answer:
gladu [14]2 years ago
4 0
The any would be -7/-3
You might be interested in
-2
Elodia [21]

Answer:

It would be the 2nd one

Step-by-step explanation:

4 0
3 years ago
Is this set of ordered pairs<br> a function?<br> (2,6), (4,9) (-2,6), (14, 11)
trasher [3.6K]

Answer:

yes :)

Step-by-step explanation:

8 0
3 years ago
On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be
Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0
3 years ago
bright pools is building a rectangular pool at a new house. The perimeter of the pool has to be 94 feet and the length has to be
bekas [8.4K]

Answer:

\displaystyle 15\:feet\:wide \\ 32\:feet\:long

Step-by-step explanation:

{2 + 2w = l

{94 = 2w + 2l

94 = 2w + 2[2 + 2w]

94 = 2w + 4 + 4w

94 = 4 + 6w

- 4 - 4

_________

\displaystyle \frac{90}{6} = \frac{6w}{6}

\displaystyle 15 = w[Plug this back into both equations above to get the length of 32 feet]; \displaystyle 32 = l

I am joyous to assist you anytime.

4 0
3 years ago
What is the solution to the compound inequality? –6 ≤ 2x + 6 ≤ 6
maw [93]

∈  ≤ ≥

-6 ≤ 2x + 6 ≤ 6 ( seperate the two inequalities)

2x + 6 ≥ - 6

2x + 6 ≤ 6 (solve the inequalities)

x ≥ -6

x ≤ 0 (find the intersection)

solution is : x ∈  { -6, 0 }

7 0
3 years ago
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