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laiz [17]
3 years ago
9

A disk-shaped grindstone of mass 1.7 kg and radius 8 cm is spinning at 730 rev/min. After the power is shut off, a woman continu

es to sharpen her ax by holding it against the grindstone for 9 s until the grindstone stops rotating.
(a)What is the angular acceleration of the grindstone?
(b) What is the torque exerted by the ax on the grindstone? (Assume constant angular acceleration and a lack of other frictional torques.)
Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

0.186 N-m        

Explanation:

mass of the grindstone, m=1.7 kg

radius, r=8 cm

Frequency, f=730 rev/min = 12.16 rev/s

time, t=9s

final angular velocity, \omega=0

Initial angular velocity,

\omega_o=2\pi f\\=2\pi (12.16) rad/s\\= 76.36 rad/s

Angular acceleration of the grind stone is:

\alpha=\frac{\omega-\omega_o}{t}\\\Rightarrow \alpha =\frac{0-76.36}{9} = -8.48 rad/s^2

Moment of inertia:

I=mr^2+mr^2=2mr^2

I=2\times 1.7 kg\times (0.08m)^2= 0.022kg-m^2

Torque exerted by the ax on the grind stone is:

\tau=I\alpha\\\tau=0.022\times (-8.48) \\\tau=0.186N-m

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3 years ago
A dielectric material is inserted between the charged plates of a parallel-plate capacitor. Do the following quantities increase
ch4aika [34]

Answer:

1. Charge on plates (plates remain connected to battery) increases.

2. Electric potential energy (plates isolated from battery before inserting dielectric) decreases.

3.Capacitance (plates isolated from battery before inserting dielectric) increases.

4. Voltage between plates (plates remain connected to battery) remains the same.

5. Charge on plates (plates isolated from battery before inserting dielectric) remains the same.

6. Capacitance (plates remain connected to battery) increases.

7. Electric potential energy (plates remain connected to battery) increases.

8. Voltage between plates (plates isolated from battery before inserting dielectric) decreases.

Explanation:

When a dielectric material is inserted between the plates of a capacitor, the capacitance is increase by a factor K, the dielectric constant.

C = KC_0

By the capacitance formula, the other factors change accordingly.

1. Charge on plates (plates remain connected to battery) increases, because charge and capacitance are directly proportional.

2. Electric potential energy (plates isolated from battery before inserting dielectric) decreases, because potential is inversely proportional to capacitance, and potential energy is given by the following formula

U = \frac{1}{2}CV^2

3.Capacitance (plates isolated from battery before inserting dielectric) increases.

4. Voltage between plates (plates remain connected to battery) stays the same, because the voltage is applied by the battery.

5. Charge on plates (plates isolated from battery before inserting dielectric) remains constant. If the plates isolated from the battery, then the total charge is conserved.

6. Capacitance (plates remain connected to battery)  increases when a dielectric is inserted.

7. Electric potential energy (plates remain connected to battery)  increases, because when plates remain connected to battery the voltage remains the same. But the capacitance increases. Therefore, electric potential energy increases.

8. Voltage between plates (plates isolated from battery before inserting dielectric) decreases, because voltage is inversely proportional to capacitance.

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olga55 [171]

Answer:

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Explanation:

It is given that,

Mass of the basketball, m = 601 g = 0.601 kg

The basketball makes an angle of 29 degrees to the vertical, it hits the floor with a speed, v = 6 m/s

It bounces up with the same speed, again moving to the right at an angle of 29 degree to the vertical. We need to find the change in momentum. It is given by :

\Delta p=mv\ cos\theta-(-mv\ cos\theta)

\Delta p=2mv\ cos\theta

\Delta p=2\times 0.601\times 6\times \ cos(29)

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