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laiz [17]
3 years ago
9

A disk-shaped grindstone of mass 1.7 kg and radius 8 cm is spinning at 730 rev/min. After the power is shut off, a woman continu

es to sharpen her ax by holding it against the grindstone for 9 s until the grindstone stops rotating.
(a)What is the angular acceleration of the grindstone?
(b) What is the torque exerted by the ax on the grindstone? (Assume constant angular acceleration and a lack of other frictional torques.)
Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

0.186 N-m        

Explanation:

mass of the grindstone, m=1.7 kg

radius, r=8 cm

Frequency, f=730 rev/min = 12.16 rev/s

time, t=9s

final angular velocity, \omega=0

Initial angular velocity,

\omega_o=2\pi f\\=2\pi (12.16) rad/s\\= 76.36 rad/s

Angular acceleration of the grind stone is:

\alpha=\frac{\omega-\omega_o}{t}\\\Rightarrow \alpha =\frac{0-76.36}{9} = -8.48 rad/s^2

Moment of inertia:

I=mr^2+mr^2=2mr^2

I=2\times 1.7 kg\times (0.08m)^2= 0.022kg-m^2

Torque exerted by the ax on the grind stone is:

\tau=I\alpha\\\tau=0.022\times (-8.48) \\\tau=0.186N-m

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Explanation:

We can use the equation:

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∑ Fc = m*ac   ⇒   N - F = m*ac = m*ω²*R    ⇒  N = F + m*ω²*R

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