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butalik [34]
2 years ago
15

Find the length of side BC. Round your answer to the nearest tenth.

Mathematics
1 answer:
Gwar [14]2 years ago
8 0

Answer: 5.4

Step-by-step explanation:

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(y^7)^3 = y^{7+3} = y^{21}.
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Graph the line x-y= -1 <br>​
hammer [34]

Answer:

y = x + 1

Step-by-step explanation:

x - y = -1

-y = -x - 1

y = (-x - 1) ÷ -1

y = x + 1

8 0
3 years ago
Please help!! Will mark brainliest!!
Natali [406]

Answer:

C

Step-by-step explanation:

it adds by 8, and if y is 14, 22, etc, then 8 would be the y in y = etc.

and if it starts ith 14, it adds by 8


3 0
2 years ago
The figure shows the layout of a symmetrical pool in a water park. What is the area of this pool rounded to the tens place? Use
k0ka [10]

Answer:

2489ft^{2}

Step-by-step explanation:

The pool are is divided into 4 separated shapes: 2 circular sections and 2 isosceles triangles. Basically, to calculate the whole area, we need to find the area of each section. Due to its symmetry, both triangles are equal, and both circular sections are also the same, so it would be enough to calculate 1 circular section and 1 triangle, then multiply it by 2.

<h3>Area of each triangle:</h3>

From the figure, we know that <em>b = 20ft </em>and <em>h = 25ft. </em>So, the area would be:

A_{t}=\frac{b.h}{2}=\frac{(20ft)(25ft)}{2}=250ft^{2}

<h3>Area of each circular section:</h3>

From the figure, we know that \alpha =2.21 radians and the radius is R=30ft. So, the are would be calculated with this formula:

A_{cs}=\frac{\pi R^{2}\alpha}{360\°}

Replacing all values:

A_{cs}=\frac{(3.14)(30ft)^{2}(2.21radians)}{6.28radians}

Remember that 360\°=6.28radians

Therefore, A_{cs}=994.5ft^{2}

Now, the total are of the figure is:

A_{total}=2A_{t}+2A{cs}=2(250ft^{2} )+2(994.5ft^{2})\\A_{total}=500ft^{2} + 1989ft^{2}=2489ft^{2}

Therefore the area of the symmetrical pool is 2489ft^{2}

3 0
2 years ago
WILL GIVE BRAINLYIST
marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

\frac{PR}{PQ} =\frac{SU}{ST}          \frac{21}{14}= \frac{6}{4}

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

A+B+C=180

46+70+C+180

116+C=180

subtract 116 from both sides

C=64

Therefore ∠Q is equal to 64 degrees

3 0
3 years ago
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