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coldgirl [10]
2 years ago
11

Easy points here pls help tho lol

Mathematics
1 answer:
pochemuha2 years ago
7 0
36 I believe
If I’m right pls give brainliest
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Start time 9:17 A.M elapsed time 5 hours and 18 minutes what is the ending time?
Mnenie [13.5K]
Answer: 2:35

reasoning for answer:

9:17 + 5:18 = 2:35
6 0
3 years ago
When csc(Theta)sin(Theta) is simplified, what is the result?
Arlecino [84]

Answer:

csc θ  ⋅  sin θ  =  1

Explanation:

csc θ  =  1 /sin θ

csc θ  ⋅  sin θ  

=  1 /sin θ  ⋅  sin θ

= sin θ/sin θ

=  1

7 0
3 years ago
Rachel has 30 pounds of a mixture of candy that sells for $1.00/lb. If lollipops sell for $0.95/lb and caramel candies sell for
Lina20 [59]

Answer:

Twenty Pounds

Step-by-step explanation:

Equation #1:

30lbs x Mix Price = (Lollipop Lbs  x 0.95)  + (Caramel Lbs X 1.10)

Equation #2:

Lollipops Lbs + Caramel Lbs = 30 Lbs

<em>Rearrange expressions to solve for different variables</em>

EQ1:   Caramel Lbs = (30 - .95 Lollipop Lbs)/ 1.10      NOTE: (mix price = 1.00)

EQ2:  Lollipop Lbs = 30 - Caramel Lbs

<em>Substitute formula 1 into formula 2</em>

Lollipop Lbs = 30 - [(30 - .95 Lollipop Lbs)/1.10]

<em>Distribute divisor</em>

Lollipop Lbs  = 30 - 27.2727 + .8636 Lollipop Lbs

<em>Collect terms</em>

Lollipop Lbs  =  2.7273 + .8636 Lollipop Lbs

<em>Remove .8336 Lollipops from both sides of the equation</em>

.1364 Lollipop Lbs = 2.7273

<em>Divide both sides by .1364  </em> (Answer is  19.9949 which rounds to 20)

Lollipop Lbs =  20

PROOF:

30 = (20 x 0.95) + (10 x 1.10)

30 = 19 + 11

30 = 30   TRUE!


6 0
2 years ago
To anyone who's in 8th grade, what did you learn in technology for 3rd quarter. like just give me the unit names or just what yo
Luda [366]

Answer:

You should probably be more specific as different schools have different curriculum's!

Step-by-step explanation:

4 0
3 years ago
Solve.<br> x² + 5x – 2=0
ExtremeBDS [4]

Answer:

1

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2

+

5

−

2

=

0

x^{2}+5x-2=0

x2+5x−2=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{5}}

b=5

=

−

2

c={\color{#129eaf}{-2}}

c=−2

=

−

5

±

5

2

−

4

⋅

1

(

−

2

)

√

2

⋅

1

Step-by-step explanation:

this should help

8 0
3 years ago
Read 2 more answers
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