Jack maclean has entered into real estate
1 answer:
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Let
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer is
the abscissa of the midpoint of the line segment is 3√2
see the attached figure
A------> <span>(5√2,2√3)
B------> </span><span>(√2,2√3)
we know that
</span>the abscissa<span> and the ordinate are respectively the first and second coordinate of a point in a coordinate system</span>
the abscissa is the coordinate x<span>
step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
</span>ABy------> midpoint AB in the coordinate y
<span>
ABx=[5</span>√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3
the midpoint AB is (3√2,2√3)
the answer is
the abscissa of the midpoint of the line segment is 3√2
see the attached figure
Answer:
A
Step-by-step explanation:
all we need to do is to plug the point (6,4) in the inequality and see if it satisfies it :
pay attention that here we have x=6 y=4
4<
we simplify we get :
4<4.5-3
4<1.5 which is incorrect so (6,4) is not a solution. moreover
notice that 4 is > than 1.5 so the point lies above the line
thus the answer is : A
you can also solve this problem by graphing the line and plotting the point (6,4) and hence you will notice that the point is above the line