Answer:
<em>La masa del paracaidista es 7.14 Kg</em>
Step-by-step explanation:
<u>Peso y Masa</u>
La masa de un objeto es una medida de la cantidad de material que el objeto posee. Sus unidades más comunes son el Kg, gr, lb, Ton.
El peso de un objeto de masa m es la fuerza con la cual la Tierra atrae al objeto a través de la aceleración de gravedad g. Sus unidades son iguales a las de cualquier fuerza, es decir, Nw, Kgf, Dina. Su fórmula es:
P=m.g
Si tenemos el peso P=70 N, podemos calcular la masa, despejándola de la fórmula:
Sustituyendo los valores:
La masa del paracaidista es 7.14 Kg
Answer:
domain: all real numbers (-∞,∞)
range: y ≤ 64
Step-by-step explanation:
since the domain is arn,
and range is the coordinates
coordniate (top or bottom-most point)
downward facing so the top
(2, 64)
since it is downward facing we use ≤ instead of ≥
y value is 64 (just as x is 2)
your answer is y ≤ 64
hope this helps:)
Answer:
9 terms
Step-by-step explanation:
Given:
1, 8, 28, 56, ..., 1
Required
Determine the number of sequence
To determine the number of sequence, we need to understand how the sequence are generated
The sequence are generated using
![\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26%26r%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
Where n = 8 and r = 0,1....8
When r = 0
![\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%260%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-0%29%210%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B8%210%21%7D%20%3D%201)
When r = 1
![\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%261%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-1%29%211%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B7%211%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%21%7D%7B7%21%20%2A%201%7D%20%3D%20%5Cfrac%7B8%7D%7B1%7D%20%3D%208)
When r = 2
![\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%262%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-2%29%212%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B6%212%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%21%7D%7B6%21%20%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%7D%7B2%20%2A1%7D%20%3D2%208)
When r = 3
![\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%263%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-3%29%213%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%21%7D%7B5%21%20%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%7D%7B3%20%2A2%20%2A1%7D%20%3D%2056)
When r = 4
![\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%264%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-4%29%214%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B4%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%20%2A%204%21%7D%7B4%21%20%2A4%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%2A5%7D%7B4%2A3%20%2A2%20%2A1%7D%20%3D%2070)
When r = 5
![\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%265%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-5%29%215%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B5%213%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%20%2A%205%21%7D%7B5%21%20%2A3%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%7D%7B3%20%2A2%20%2A1%7D%20%3D%2056)
When r = 6
![\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-6%29%216%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B6%212%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%20%2A%206%21%7D%7B6%21%20%2A%202%20%2A1%7D%20%3D%20%5Cfrac%7B8%20%2A%207%7D%7B2%20%2A1%7D%20%3D%2028)
When r = 7
![\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%267%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-7%29%217%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B7%211%21%7D%20%3D%20%5Cfrac%7B8%20%2A%207%21%7D%7B7%21%20%2A%201%7D%20%3D%20%5Cfrac%7B8%7D%7B1%7D%20%3D%208)
When r = 8
![\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%26%268%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B8%21%7D%7B%288-8%29%218%21%7D%20%3D%20%5Cfrac%7B8%21%7D%7B8%210%21%7D%20%3D%201)
The full sequence is: 1,8,28,56,70,56,28,8,1
And the number of terms is 9
For this ones the second value is always negative so A is not correct. Also they have to have an exact square root which 50 doesn't. So the answers are B and C
(a-6)(a+6)
(w-11)(w+11)
Http://www.madeiracityschools.org/userfiles/376/Classes/17052/Review%20Worksheet%20Unit%209%20Quiz%2...
I would use this website. Hope it helps!
