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3 years ago

I swear this is my last i-ready question lol

Mathematics

2 answers:

stellarik [79]3 years ago

6 0

Area: 49

Brainly wants me to type more stuff soo hsdfghng

drek231 [11]3 years ago

3 0

The area is 49 hopefully this is right have a nice day

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A neighborhood swim club charges a one-time fee of $25 to join and $85 each month. If n is the number of months of membership an

zepelin [54]

The independent variable would be n.

5 0

3 years ago

Please help me solve question (d) f(3)+f(-3).

Y_Kistochka [10]

F(3): 6-3(3)=6-9=-3
f(-3): 6-3(-3)=6-(-9)=6+9=15
-3+15=12

5 0

4 years ago

2y to the power 4 x 5y to the power 3

iogann1982 [59]

Answer:

(2*5y^7)

Step-by-step explanation:

STEP

Equation at the end of step 1

(2y4 • 5) • y3

STEP

Equation at the end of step 2

(2•5y4) • y3

STEP

Multiplying exponential expressions :

3.1 y4 multiplied by y3 = y(4 + 3) = y7

Final result :

(2•5y7)

5 0

3 years ago

An election forecasting model has a 50:50 chance of correctly predicting the election winner when there are two candidates. Befo

Blababa [14]

Answer:

Te correct answer is c) 0.750

Step-by-step explanation:

Lets call:

A = {Allan wins the election}

B = {Barnes wins the election}

MA = {the model predicts that Allan wins}

MB = {the model predicts Barnes wins}

We know that the model has a 50:50 chance of correctly predicting the election winner when there are two candidates. Then:

P(MA | A) = 0.5 = P(MA | B)

P(MB | B) = 0.5 = P(MB | A)

The prior probability P(A) given by the election researcher is 0.75

We must find the posterior probability P(A | MB)

We use Bayes theorem:

$P(A|MB) = \frac{P(MB|A)P(A)}{P(MB)} = \frac{0.5*0.75}{0.5} = 0.75$

We used the result:

$P(MB) = P(MB|A)P(A) + P(MB|B)P(B) = 0.5*0.75+0.5*0.25=0.5$

7 0

4 years ago

Is 6xyz and 8xy like terms

Korolek [52]

You can combine variables that are the same such as 6x and 8x, and y and y. that would end up being 14x+2y+z

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3 years ago