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3 years ago

Cheri walked 12 blocks in 36 minutes. What was Cheri's speed per minute?

Mathematics

2 answers:

monitta3 years ago

5 0

3 blocks per minute, because 36/12=3

Vesnalui [34]3 years ago

3 0

3 is the speed per minute!

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Help please! Will give brainiest if correct!

frosja888 [35]

Slope is 3/4
You are welcome

4 0

3 years ago

Read 2 more answers

What is the value of a in the equation 3a+b=54, when b=9?

insens350 [35]

3a+9=54

3a+9-9=54-9

3a= 45

a=15

Check answer:

3(15)+9=54

54=54

Answer is a=15

3 0

3 years ago

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lbvjy [14]

Answer:

$\sf \: \fbox{Option C) \: The salary of B is 6000₹}$

Step-by-step explanation:

Let the salary or A is x and salary of B is y.

now,

Condition one,The sum of 3/4th of A’s salary and 5/3rd of B’s salary is ₹16,000.

writing above statement in equation form,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000$

Multiplying above equation with twelve,

$\sf \frac{3x}{4} + \frac{5y}{3} = 16000 \\ \sf \frac{12 \times 3x}{4} + \frac{12 \times 5y}{3} = 16000 \times 12 \\ \sf \fbox{9x + 20y = 192000} \rightarrow eq. 1$

and condition two,

The difference of their salaries is ₹2000

$\sf \: x - y = 2000$

Multiplying above equation with 20

$\sf \fbox{\: 20x -20y = 40000} \rightarrow eq.2$

On adding equation 1 and equation 2,

$\sf9x + \cancel{20y} = 192000 \\ \sf 20x - \cancel{20y} = 40000 \\ \hline \sf 29x + 0y = 232000 \\ \sf x = \frac{232000}{29} \\ \sf \: \fbox{x = 8000₹}$

Substituting the value of x in,

$\sf \: x - y = 2000 \\ \sf \: 8000 - y = 2000 \\ \sf \: y = 8000 - 2000 \\ \sf \fbox{y = 6000₹}$

$\sf \: \fbox{The salary of B is 6000₹}$

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5 0

2 years ago

Solve the system by substitution x+4y=14 and 3x+4y=22

love history [14]

Answer:

x=4,y=5/2 or (4,5/2) depending on the type of answer you need .

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu

Lina20 [59]

Answer:

a) 0.5

b) 0.5

c) 0.67

d) 1

e) 0.83

f) 0.67

Step-by-step explanation:

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

n(S)= Total number of outcome of an experiment=6

P(A)=3/6=1/2=0.5

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

A-C={1,3,5}-{1,3,9,11}={5}

(A-C)∪B={5}∪{7,9,11}={5,7,9,11}

P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0

4 years ago