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Lelu [443]
2 years ago
11

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the

earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable. Which equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake? M = log StartFraction I Over S EndFraction M = log (10 S) M = log StartFraction 10 S Over S EndFraction M = log StartFraction 10 Over S EndFraction.
Mathematics
1 answer:
uranmaximum [27]2 years ago
5 0

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

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D&E, A&B

Step-by-step explanation:

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7 0
3 years ago
Solve: x2 − x − 6/x2 = x − 6/2x + 2x + 12/x After multiplying each side of the equation by the LCD and simplifying, the resultin
Vesna [10]

The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}

Multiply both the sides by x.

\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}

Again multiply both the sides by x

2x^{2} -2x-12 = 5x^{2} +18x

\implies 5x^{2} -2x^{2} +18x +2x +12 = 0

\implies 3x^{2} + 18x+2x + 12 = 0

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

brainly.com/question/2976807

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7 0
2 years ago
1. You have two playing cards with a sum of (−12) in your hand.
Verdich [7]
Yes the person is right I was trying to type it but they beat me to it
3 0
3 years ago
495x43
Mashcka [7]

Answer:a) $5.64  b)  21 ounces of tea leaves

Step-by-step explanation:

Step 1

5 ounces of tea leaves can be bought with  $2.35

1 ounce of tea can be bought with =$2.35/5 =$0.47

12 ounces at the same rate  can be bought with

=12 x $0.47 = $5.64

b) 5 ounces of tea leaves can be bought with  $2.35

? Ounces of tea leaves can be bought with $10

$2.35 =5 ounces of tea

$10 = ? ounces of tea

           = (10 x  5)/2.35

           =50/2.35

=21.27 rrounded to 21 ounces of tea leaves

5 0
3 years ago
Helpp PLEASE HELP PLEASE PLEASE PLEASEE!
Katyanochek1 [597]
Volume = lwh (we are already told the volume, length, and width, so we can rearrange the formula to find height)

l=V/wh
= 270/15(9)
=270/135
=2 m

This means the height of the pool is 2m, hope this helps!! :)

6 0
3 years ago
Read 2 more answers
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