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skad [1K]
3 years ago
9

Calculate the area of a circle with a diameter of 0, 8m​

Mathematics
2 answers:
dlinn [17]3 years ago
6 0

Answer:

50.24=4squared times pie

Step-by-step explanation:

gizmo_the_mogwai [7]3 years ago
5 0

Answer:

The area of a circle with a diameter of 0.8 meters is approximately 0.50 m^2.

Step-by-step explanation:

Since the diameter of the circle is 0.8 meters, that means the radius of the circle would be 0.4 meters. The area of a circle can be found by the formula \pi r^2, where r represents the radius of the circle. In this case, the area would be 0.4^2*\pi = 0.16 * \pi ≈ 0.50 m^2.

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There are 16 white balloons, 24 red balloons. Each arrangement must be identical. What is the greatest number of arrangements yo
katovenus [111]

Answer:

8

Step-by-step explanation:

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4 0
3 years ago
Z divided by 3-2z + 4(z-8) when z = 18 <br><br> A. -122<br> B. 6<br> C. -66<br> D. 10
murzikaleks [220]

Everywhere you see z, replace the letter with 18.

z/[(3- 2z)] + 4(z - 8)

18/[(3 - 2(18))] + 4(18 - 8)

You finish.

3 0
3 years ago
Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.
sattari [20]
Let A= <span>2 – 11x2 – 8x + 6x2, the standard form of A is 
     A = - 5x² -8x + 2

</span>
7 0
3 years ago
Read 2 more answers
Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10
Mashutka [201]

\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

2 \: ( \: x + 1 \: ) - 3

Plugging in the value "x\:=\:6" in the above expression, we have

= 2 \: ( \: 6 + 1 \: ) - 3

= 2 \: ( \: 7 \: ) - 3

= 14 - 3

= 11

<h3><u>Note</u>:-</h3>

\sf\red{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

5 0
3 years ago
What are the solutions to the following system? StartLayout Enlarged left-brace 1st row negative 2 x squared + y = negative 5 2n
Yakvenalex [24]

Answer:

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

Step-by-step explanation:

we have

-2x^{2} +y=-5 ----> equation A

y=-3x^{2} +5 -----> equation B

solve by substitution

substitute equation B in equation A

-2x^{2} +(-3x^{2} +5)=-5

solve for x

-5x^{2} +5=-5

-5x^{2}=-10

x^{2}=2

x=\pm\sqrt{2}

<em>Find the value of y</em>

y=-3x^{2} +5

For x=\sqrt{2} ----> y=-3(\sqrt{2})^{2} +5=-1

For x=-\sqrt{2} ----> y=-3(-\sqrt{2})^{2} +5=-1

therefore

The solutions are

(\sqrt{2},-1),(-\sqrt{2},-1)

(StartRoot 2 EndRoot, negative 1) and (negative StartRoot 2 EndRoot, negative 1)

8 0
4 years ago
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