we know that Bob can do the whole job in 14 hours, how much of the work has he done in 1 hour only? well since he can do the whole lot in 14 hours in 1 hour he has only done 1/14 th of the job.
we know that James can do it in 18 hours, a bit slower, so in 1 hour he has done only 1/18 th of the job.
let's say it takes both of them working together say "t" hours, so in 1 hour Bob has done (1/14) of the work whilst James has done (1/18) of the work, the whole work being t/t or 1 whole, so for just one hour that'd 1/t done by both Bob and James.

The answer will be C
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5/2 , /5 , 2.71 (71 Repeating) , 2 3/4
Usually, the more often it's compounded, the better. That's assuming that the percent is equal through all comparisons, however.
Answer:
m<EDA=35°
m<DAE=35 diagonal bisect it
Step-by-step explanation:
m<AED=180-2×35=110°(by sum of interior angle of the triangle)
m<BCE=mDAE=35° alternate angle
Answer: 1x+0
Step-by-step explanation:
Put the like terms together I believe