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AnnZ [28]
4 years ago
14

Find f(3)... if f(x)=x^4+2x^2-1

Mathematics
2 answers:
Bogdan [553]4 years ago
6 0

Just substitute 3 for every X value (3)^4+2(3)^2-1 it will give you 98


Marrrta [24]4 years ago
6 0

For this case we have the following function:

f (x) = x ^ 4 + 2x ^ 2-1

What we must do is evaluate the value of x = 3 in the given function.

We have then:

f (3) = (3) ^ 4 + 2 (3) ^ 2-1

Then, Rewriting the function we have:

f (3) = (3) ^ 4 + 2 (3) ^ 2-1

f (3) = 81 + 18-1

f (3) = 98

Answer:

The value of the function evaluated for x = 3 is given by:

f (3) = 98

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Read 2 more answers
Consider a function <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B%281%20-%20x%29%5E2%7D%7B%281%20%2B%20x%29%5E2%
SCORPION-xisa [38]

Answer:

f=

x2−2x+1

x3+2x2+x

Step-by-step explanation:

Let's solve for f.

fx=

(1−x)2

(1+x)2

Step 1: Multiply both sides by x^2+2x+1.

fx3+2fx2+fx=x2−2x+1

Step 2: Factor out variable f.

f(x3+2x2+x)=x2−2x+1

Step 3: Divide both sides by x^3+2x^2+x.

f(x3+2x2+x)

x3+2x2+x

=

x2−2x+1

x3+2x2+x

f=

x2−2x+1

x3+2x2+x

8 0
4 years ago
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