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3 years ago

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Two golfers completed one round of golf. The first golfer had a score of +6 and the second golfer had a score of –3. How many mo

re shots did the first golfer take? 17. What is the balance as a result of having a credit of $84 and a debit of $29?

1 answer:

Monica [59]3 years ago

6 0

Question 16

Given that two golfers completed one round of golf.

It is stated that the first golfer had a score of +6 and the second golfer had a score of -3.

Let suppose 'x' be the number of shots the first golfer took.

It is clear that the first golfer is 6 over par, while the second golfer is under 3.

Thus, the equation becomes:

$-3 + x = 6$

adding -3 to both sides

$-3+3+x = 6+3$

simplify

$x = 9$

Thus, the second golfer has taken 9 more shorts.

Question 17

When we talk about credit, it means:

Credit = +

When we talk about debt, it means:

Debit = -

Thus,

Credit = +84

Debt = -29

Balance = 84 + (-29)

= 84 - 29

= 55

Thus, the balance is: 55

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2 years ago

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Step-by-step explanation:

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3 years ago

If point Q(3,-4) is rotated +270° about the origin, what are the coordinates of Q?

erica [24]

Answer:

$Q' =(-4,-3)$

Step-by-step explanation:

Given

$Q = (3,-4)$

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Required

Determine the new coordinates of Q (i.e. Q')

When a point (x,y) is rotated +270° about the origin, the new coordinates is: (y,−x)

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3 years ago

Are the fractions 1/5 , 5/5 , and 5/1 equivalent?Explain.

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5/5, or five fifths, is a whole. any number divided by itself is automatically one, so it is like making another pie and cutting it into five pieces, only this time no one eats any of it because it's burned or something. At the end, you have five pieces of pie

5/1 is actually just another way of writing plain old 5. To keep the pie example rolling, you have five pies, and no one eats any of these either, so they are all yours. You have 5 pies divided between one person, so at the end of the day you have 5 whole pies.

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3 years ago

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Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and

Ray Of Light [21]

Answer:

A. $g'(3)=-\frac{1}{2}$

Step-by-step explanation:

We have been given that f be a differentiable function such that $f(3)=15$ , $f(6)=3$ , $f'(3)= -8$ , and $f'(6)= -2$ . The function g is differentiable and $g(x)= f^{-1} (x)$ for all x.

We know that when one function is inverse of other function, so:

$g(f(x))=x$

Upon taking derivative of both sides of our equation, we will get:

$g'(f(x))*f'(x) =1$

$g'(f(x))=\frac{1}{f'(x)}$

Plugging $x=6$ into our equation, we will get:

$g'(f(6))=\frac{1}{f'(6)}$

Since $g(x)= f^{-1} (x)$ , then $g'(f(6))=g'(3)$ .

$g'(3)=\frac{1}{f'(6)}$

Since we have been given that $f'(6)= -2$ , so we will get:

$g'(3)=\frac{1}{-2}$

$g'(3)=-\frac{1}{2}$

Therefore, $g'(3)=-\frac{1}{2}$ and option A is the correct choice.

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