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blagie [28]
3 years ago
6

Andre constructs the image of line n under a dilation centered at point O that is not on line n. Becca construct a different ima

ge of line n under a dilation centered at point O. what can you conclude about andre's and becca's lines?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
6 0
<em /><u><em /></u>I think that both lines will show only 1 line because 1 line will be on top of the other. I believe this because both lines are dilated with its center at point O which does not lie on line n. Whatever dilation Andre uses may also be the dilation used by Becca since their lines centered at point O. Both lines will have the same slope and share the same coordinates.
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Answer:

The graph is a line with a gradient of 2/5, and which runs through the coordinate (0, 800) and (0, -2000).

Step-by-step explanation:

You can graph any line by drawing a line through two points that are on that line, and thus are part of the magical equation, which accounts for the description of any point on that line.

In fact that is exactly how a computer draws a graph. It plots a dot, wich coordinates are calculated by substituting a value in the formula. Next it does that for another coordinate, very close to the first one. Now you have two dots next to each other... and so on.

Because computers can calculate extremely fast, within an instant, the result is a plotted chart, which in this case looks like the graph of a line.

It's graph is a line with a gradient of 2/5, which goes through the y-axis at the coordinate (0, 800).

You could find another pont on this line, by randomly choosing a simple number for x and substituting that value in the equation. For an example, you could substitute x =2 in y=2/5x+800.

y = 2/5x+800

x = 2

y = 2/5*(2)+800

y = 10/5+800

y = 2+800

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So you now have another point (5, 802)

In general it is best to search for the value of x, when you substitute y = 0.

y = 2/5x + 800

y = 0

0 = 2/5x + 800

2/5x = ( -800 )

x = 5/2 * ( -800 )

x = -4000 / 2

x = -2000

So you now have another point ( which goes through the x-axis ) at the coordinate (0, -2000).

Now you can draw the graph of y=2/5x+800.

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