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BabaBlast [244]
3 years ago
8

Jessica's teacher asks a class to find the largest number that is smaller than 4.5. Jessica's friend Jeevan gives the answer 4.4

. a Why is Jeevan not correct?​
Mathematics
1 answer:
Ber [7]3 years ago
5 0
4.4 is not a whole number so it isn’t the largest number that is also less than 4.5. The correct answer could be 4
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A rectangular room is 4 yards long and 5 yards wide . Lucas is covering the floor with tiles that are 1 square foot . How many t
12345 [234]

Answer:

I think like 21

Step-by-step explanation:

i think it correct but if it not it okay but alaest I try my best on it

4 0
3 years ago
Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.
Gnoma [55]
For the answer to the question above, I'll explain my answer through an equation below.
<span>5+10>x,x<15
5+x>10
x>10-5
or x>5
</span>So the answer is either multiple choice letter C. 6 or multiple choice letter D. 11

I hope my answer helped you. Have a nice day!
7 0
3 years ago
2p + 3x = 680 x = 2p
svlad2 [7]
Use substitution. 

2p + 3(2p) = 680
2p + 6p = 680
8p = 680
p = 85

Plug in.
x = 2p
x = 2(85)
x = 170
p = 85
3 0
3 years ago
Read 2 more answers
Question 3<br> 1 pts<br> 2 and -2 are 4 units apart on the number line.<br> True<br> False
EastWind [94]
It’s actually true!

^ ^ ^ ^
<—|——|——|——|——|—>
-2 -1 0 1 2

The 4 arrows above the number line represents the distance between 2 and -2 which is 4!
4 0
3 years ago
Solve for X, (with steps please) <br> 0.46=0.527-[0.0562/2 * log(0.1+x/1.5-x)]
Ivanshal [37]
Rearrange the equation: 

\frac{0.0562}{2} * log( \frac{0.1+x}{1.5 - x}) = 0.527 - 0.46 = 0.067

Isolate the log on its own

log (\frac{0.1 + x}{1.5 - x}) = \frac{0.067*2}{0.0562} = 2.42 (2dp)

To get rid of the log you must do 10^2.42 

\frac{0.1 +x}{1.5-x} = 10^{2.42} = 242.29 (2dp)

Then multiply both sides by (1.5 - x)

0.1 +x = 242.29(1.5-x)

0.1 + x = 363.44 - 242.29x

Solve normally

243.29x = 363.34    x = 363.34/243.29    x= 1.49344    x= 1.49 (2dp)

Hope that helps. Please send me a message if there's patchy bits. Also I'm sure you'll figure this out, but just in case, anywhere I've put down a 2dp shows that I've rounded the number to 2 decimal places. It becomes a pain to deal with otherwise. 

3 0
4 years ago
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