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BabaBlast [244]

3 years ago

8

Jessica's teacher asks a class to find the largest number that is smaller than 4.5. Jessica's friend Jeevan gives the answer 4.4

. a Why is Jeevan not correct?

1 answer:

Ber [7]3 years ago

5 0

4.4 is not a whole number so it isn’t the largest number that is also less than 4.5. The correct answer could be 4

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Simplify 2[(9 - 5)^5 / 8]

Alenkinab [10]

2[(9 - 5)^5/8] = 2[4^5/8] = 2[1024/8] = 2[128] = 256

5 0

4 years ago

A projector enlarges an image in the ratio 20:1. What will be the size of an enlargement of a picture that is 8cm by 6cm?

nydimaria [60]

Answer:

160 cm × 120 cm

Step-by-step explanation:

this means 1 cm turns into 20 cm.

so, 8 cm × 6 cm becomes

8×20 = 160 cm × 6×20 = 120 cm

3 0

1 year ago

On Monday, 288 students went on a trip to the zoo. All 7 buses were filled and 8 students had to travel in cars. How many studen

olchik [2.2K]

Answer:

40 kids

Step-by-step explanation:

288 minus the 8 kids that had to hide in cars= 280. 280 divided by the seven busses is 40

8 0

3 years ago

Sita and Radha purchased a car for rupees 320000 due to some economic problem they sold it for 280000.find the loss incured and

musickatia [10]

Answer:

40000 and 12.5% respectively

Step-by-step explanation:

soln:

given,

cost price(c.p)=320000

selling price(s.p)=280000

loss(l),loss percentage(l%)=?

we know,

l=c.p-s.p

or,l=320000-280000

•°•l=40000

now,

l%=l/c.p*100%

or,l%=40000/320000*100%

•°•l%=12.5%

6 0

3 years ago

For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for

dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

$T_{f} = T_{p} -T_{s} = K_{f}$ * (morality of solution)

$T_{p}$ and $T_{s}$ are the freezing points of the pure solvent (water, 0°C) and $K_{f}$ = freezing point depression constant of water. Therefore,

$T_{f} = K_{f}$ *(0.859 m)

=====> (0°C) – (3.00°C) = $K_{f} *(0.859 m)$

=====> -3.00°C = $K_{f} *(0.859 m)$

Ignore the negative sign (since $K_{f}$ is positive) and get

$K_{f}$ = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0

3 years ago