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r-ruslan [8.4K]
2 years ago
6

Finding the Roots/Zeros

Mathematics
1 answer:
boyakko [2]2 years ago
3 0

Answer:

  x = {-√7, √7, -i, i}

Step-by-step explanation:

The quartic can be factored as the product of two quadratics:

  f(x) = x^4 -6x^2 -7

  f(x) = (x^2 -7)(x^2 +1)

Each quadratic can be factored according to the factoring of the difference of squares:

  x^2 -a^2 = (x -a)(x +a)

Of course, the square root of a negative number is imaginary. The full factorization is then ...

  f(x) = (x -√7)(x +√7)(x -i)(x +i)

The zeros are ...

  x = {-√7, √7, -i, i}

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Is that the answer u needed?

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