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Sedbober [7]
2 years ago
15

The number of Calories burned while running varies directly with the number of miles run. Francesca burns 816 Calories on her 8-

mile run. Write a direct variation equation to represent this relationship.
Mathematics
1 answer:
Alla [95]2 years ago
4 0

Answer:

y = 102*x

Step-by-step explanation:

y=a*x

x: distance

y: calories

816=a*8

a= 816/8= 102

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The sum of two numbers a and b is 7 and the difference between them is 2. What is the value of a x b ? Give your answer as a mix
Andre45 [30]

Answer:

45/4

Step-by-step explanation:

We can interpret the question to have two equation which can be solve simultaneously

a+b=7------------(1)

a-b=2------------(2)

From eqn(2) make a subject of formula

a=2+b--------(3)

Substitute the (3) into eqn(1)

a+b=7------------(1)

2+b+b=7

2b=7-2

2b=5

b=5/2

From equation (3) substitute value of b to find a

a=2+b--------(3)

a= 2+5/2

a=9/2

Then What is the value of a x b ?

9/2× 5/2

=45/4

8 0
2 years ago
Find the value of x. Round to the nearest tenth.
serg [7]

Answer:

Where is the equation?

Step-by-step explanation:

8 0
3 years ago
12 plus 2 times a number is 6 times the number. what is the number?
DedPeter [7]

Answer:

X=3

Step-by-step explanation:

12+2x=6x

7 0
2 years ago
Read 2 more answers
The sequence a1 = 6, an = 3an-1 can also be written as
wariber [46]
The question as presented is incomplete, here is the complete question with the multiple choice:

The sequence a1 = 6, an = 3an − 1 can also be written as:

1) an = 6 ⋅ 3^n
2) an = 6 ⋅ 3^(n + 1) 
3) an = 2 ⋅ 3^n
4) an = 2 ⋅ 3^(n + 1)

The correct choice is option 3) an = 2⋅3^n.

If we look at the initial sequence an = 3⋅an-1, and

a1 = 3⋅a0 = 6
a0 = 6/3
a0 = 2

We can now look at the sequence.

a0 = 2
a1 = 6
a2 = 18
a3 = 54
etc...

A common factor in each of those numbers is 2, so we can rewrite the sequence by factoring out 2.

a0 = 2⋅1
a1 = 2⋅3
a2 = 2⋅9
a3 = 2⋅27

The numbers being multiplied by 2 are all factors of 3. So we can rewrite the sequence again as:

a0 = 2⋅3^0
a1 = 2⋅3^1
a2 = 2⋅3^2
a3 = 2⋅3^3

This sequence can now be rewritten as an = 2⋅3^n.
7 0
2 years ago
Help me with this please ​
Bess [88]

Answer:

A

Step-by-step explanation:

Brainliest PLEASE

3 0
2 years ago
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