Question

Valerie and Seth are measuring the outside walls of a house using two different instruments. They want to find the house's perimeter. Valeria measured the north and east sides while Seth measured the west and south sides. Their results are listed in the table.
Part A
Use decimal numbers to write an expression that represents the length of the walls that Valerie measured.

Part B
Now use decimal numbers to write an expression that represents the length of the wall that Seth measured.

Part C
Write an expression for the perimeter of the house. Use the work you completed in part A & B to guide you.

Part D
Simplify the expression from part C to find the perimeter of the house in feet.

Part E
Suppose that you evaluate the expression for Valerie's wall and the expression for Seth's wall separately. Then you add the two expressions together. Will you get the same answer that you arrived at in part D? Why or why not? Show your work to prove your case.​

PLEASE PLEASE PLEASE HELP I REALLY NEED HELP IN THIS WORK, THANK YOU.

Answer 1

Answer:

Part A. (2.5×4)+(21.25×3)=32

Part B. 3.5+(22.75×2)+58

Part C. (2.5x4)+(21.25×3)+32+3.5+(22.75×2)+58

Part D. Perimeter is 212.75ft

Part E. The Sum of 105.75ft and 107ft is 212.75ft. The Commutative Property allows me to add numbers in any order. This is why the answers in parts D and E match.

Step-by-step explanation:

Answer 2

Answer:

A)

Valerie measured 4 walls at 2 1/2 feet. In decimal form, each wall is 2.5 feet long. So, the total length of the 4 walls is (2.5 × 4) feet.

Valerie measured 3 walls at 21 1/4 feet. In decimal form, each wall is 21.25 feet long. So, the total length of the 3 walls is (21.25 × 3) feet.

Valerie measured 1 wall at 32 feet.

The expression that gives the total length of the walls that Valerie measured is (2.5 × 4) + (21.25 × 3) + 32.

B)

Seth measured 1 wall at 3.5 feet.

Seth measured 2 walls at 22.75 feet. So, the total length of the 2 walls is (22.75 × 2) feet.

Seth measured 1 wall at 58 feet.

The expression that gives the total length of the walls that Seth measured is 3.5 + (22.75 × 2) + 58.

C)

The total length of Valerie’s walls is (2.5 × 4) + (21.25 × 3) + 32.

The total length of Seth’s walls is 3.5 + (22.75 × 2) + 58.

To find the expression for the perimeter of the house, add Valerie’s expression to Seth’s:

(2.5 × 4) + (21.25 × 3) + 32 + 3.5 + (22.75 × 2) + 58.

D)

(2.5 × 4) + (21.25 × 3) + 32 + 3.5 + (22.75 × 2) + 58

= 10 + 63.75 + 32 + 3.5 + 45.5 + 58

= 212.75

The perimeter of the house is 212.75 feet.

E)

The total length of Valerie’s walls is 105.75 feet:

(2.5 × 4) + (21.25 × 3) + 32 = 10 + 63.75 + 32 = 105.75 feet.

The total length of Seth’s walls is 107 feet:

3.5 + (22.75 × 2) + 58 = 3.5 + 45.5 + 58 = 107 feet.

The sum of 105.75 feet and 107 feet is 212.75 feet. The Commutative Property allows me to add numbers in any order. This is why the answers in parts D and E match.

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