Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
The solution is mathematically given as
- P(X=3)= 0.17
<h3>What is the
solution ?</h3>
Generally, the equation for the Probability of P(X=3) is mathematically given as
b)
Therefore
P(X=3)= 0.17
c)
a)
Read more about cumulative probability distribution.
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A=P(1+R)^n
A=amount in 10 years
P=original amount (200)
R=rate(o.o6)
n=number of times compunded(20)
A=200x1.06^20
=641.4270944
Therefore Rachel will have 641.42 in 10 years
Circumference= diameter x pi
12x3.14 = 37.68
Answer:
10
Step-by-step explanation: