Answer:
W = kq1q2 / r
Step-by-step explanation:
W varies jointly as the product of q1 and q2 and inversely as radius r
Product of q1 and q2 = q1q2
W = (k*q1"q2) / r
W = kq1q2 / r
Where,
W = work
q1 = particle 1
q2 = particle 2
r = radius
k = constant of proportionality
The answer is W = kq1q2 / r
Its 2,9 because thats the highest it gets which is the maximum
The sequence of transformation will be;
Rotate 120 degrees Counterclockwise around B, then Translate B to B' and reflect over segment BA.
<h3>How to Identify the Transformation?</h3>
We want to find the transformation that maps Quadrilateral ABCD onto Quadrilateral A'B'C'D'.
Looking at the given image, the sequence of transformation will be;
Rotate 120 degrees Counterclockwise around B, then Translate B to B' and reflect over segment BA.
Read more about Transformations at; brainly.com/question/4289712
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Answer:
i think it is negative
Step-by-step explanation:
Step-by-step explanation:
6x + 2 = y --------1
3y - 18x = 12 -----2
From 1
substitute y = 6x +2 in equation 2
3(6x + 2) - 18x = 12
18x + 6 - 18x = 12
Therefore, no solution!
