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Elza [17]
3 years ago
8

A storekeeper increased the price of hats by 5%.

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Answer: c = 1.05p

Step-by-step explanation:

Price of the hat = p

Percentage increase in the price of the hat = 5%

The equation to calculate the increase of the total cost, c, of the hat will be:

c = p + (5% × p)

= p + (5/100 × p)

= p + (0.05 × p)

= p + 0.05p

c = 1.05p

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Select al solutions to the inequality 8t< -2t+20
DENIUS [597]

Step-by-step explanation:

the answer is E

which 2

its easy bro

6 0
3 years ago
Jake and Gloria are running on the track team. Gloria can run twice as many miles as
Tanzania [10]

Answer:

J+2J=12 so 3J=12 so J=4

Step-by-step explanation:

Use J to represent Jake's miles.

We know that Gloria's miles (G) is twice J, so G=2J

We also know that Jake and Gloria together ran 12 miles.

So we know, J+2J=12 or 3J=12   meaning J=4

So Jake runs 4 miles, and since Gloria is two times that she ran 8 miles.

6 0
4 years ago
Hurry please...
Eva8 [605]

Answer:

initial value=2

rate of change=1

Step-by-step explanation:

rate of change=(3-2)/(1-0)=1

7 0
4 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
Please show me how you got the answer thanks.
andriy [413]
85/11.9 whatever that works out to
5 0
3 years ago
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