This is an incomplete question, the image is shown below.
Answer : The fraction empty container is,
Step-by-step explanation :
As we are given that:
The capacity of container = 60 mL
In the given figure, the container is filled with 25 mL.
That means,
60 - 25 = 35 mL container is empty.
Now we have to calculate the fraction of it is empty.
The fraction of it is empty =
The fraction of it is empty =
The fraction of it is empty =
Therefore, the fraction empty container is,
Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
