Question

Find the equation of the line that passes through the point (-5,7) and is perpendicular to the line y=-x+12.

Answer 1

Answer:

y=x+12

Step-by-step explanation:

y=-x+12; is a line with slope m1=-1

to find perpendicular slope of intersecting line take the negative inverse of m1. so -1*(1/(-1))=1=m2

use equation for a line of y=m*x+b and put in the point (-5,7) and solve for b=the y axis intercept

7=1*(-5)+b

7=-5+b

12=b

so

y=x+12