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rusak2 [61]
3 years ago
9

Evaluate 15+ (29-13)=

Mathematics
1 answer:
leonid [27]3 years ago
6 0
The answer is 31
29 - 13 is 16
16 + 15 is 31
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Please answer questions 1-6 i’ll mark as brainliest<3
Vikki [24]
Yea I’m good too much
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3 years ago
Coordinates will be fine PLs ASAP cause I need this rn<br> 13 POINTS!!!
grigory [225]

If the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Given,

The vertices of the triangle = J(-3,-5), K(-2,2) and L(1,-4)

We know,

In reflection in y axis (x,y)  will become (-x,y)

Then the vertices of the reflection in y axis = J(3,-5), K(2,2) and L(-1,-4)

Draw the triangle using the vertices.

Hence, if the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Learn more about reflection here

brainly.com/question/15487308

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3 0
1 year ago
What is the value of x in the equation 4 and StartFraction 3 Over 10 EndFraction minus (2 and two-fifths x + 5 and one-half) = o
musickatia [10]

Answer:

5

Step-by-step explanation:

Edge i think dont quote me on this plz

3 0
3 years ago
Suppose you buy 4 buckets of apples and 5 buckets of peaches for $64. If you bought 8
Sophie [7]

Option D is the correct answer.

Step-by-step explanation:

Step 1 :

Let A represent the cost of one bucket of apple and P represent the cost of one bucket of peaches.

So we have ,

4 buckets of apples and 5 buckets of peaches for $64

8  buckets of apples and 3 buckets of peaches for $72

Writing this in the equation form we have,

4A + 5P = 64

8A + 3P = 72

Step 2:

Solving for the above 2 equations we can get the required costs

Equation 1 is

4A + 5P = 64 , Multiplying this by 2 we have 8A + 10P = 128

Equation 2  = 8A + 3P = 72

Subtracting both we have , 7p = 56 = > P = 8

Substituting this in equation 1 we have

8A + 80 = 128 => A = 6

Hence the cost of one bucket of apple is $6 and the cost of one bucket of apple is $8.

Option D is the correct answer.

3 0
3 years ago
Read 2 more answers
Find two different 2 by 2 matrices a and b such that ab=ba
stiv31 [10]
Let \mathbf A=\mathbf I be the identity matrix. Then pick whatever matrix you like for \mathbf B.
8 0
3 years ago
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