Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
(x,y) = (r,16)
With this knowledge, plug in r for x, and 16 for y
16 = 2(r) - 4
Isolate the r, add 4 to both sides
16 (+4) = 2r - 4 (+4)
20 = 2r
Divide 2 from both sides
20/2 = 2r/2
r = 20/2
r = 10
hope this helps
Answer: x=−5 or x=5
Step-by-step explanation:
−3x4+27x2+1200=0
Step 1: Factor left side of equation.
−3(x2+16)(x+5)(x−5)=0
Step 2: Set factors equal to 0.
x2+16=0 or x+5=0 or x−5=0
x=−5 or x=5
