Please see the <em>blue</em> curve of the image attached below to know the graph of the function g(x) = (1/3) · 2ˣ.
<h3>How to graph a transformed function</h3>
Herein we have an <em>original</em> function f(x). The <em>transformed</em> function g(x) is the result of <em>compressing</em> f(x) by 1/3. Then, we find that g(x) = (1/3) · 2ˣ. Lastly, we graph both function on a <em>Cartesian</em> plane with the help of a <em>graphing</em> tool.
The result is attached below. Please notice that the <em>original</em> function f(x) is represented by the red curve, while the <em>transformed</em> function g(x) is represented by the blue curve.
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Answer:90
Step-by-step explanation:
the angle is perpendicular
Answer:
8 3/25 because 8.12 is 8 12/100 and when you simplify 12/100 you get 3/25
Answer: The initial volume is 593.76mL
Step-by-step explanation:
As you do not say anithing about the pressure, i guess that the pressure remains constant.
If the gas is an ideal gas, we have:
P*V = n*R*T
where P is pressure, n is number of moles and R is a constant.
Now, initially we have:
P*Vi = n*R*315°C
finally we have:
P*825mL = n*R*452°C
Now we can take the quiotient of those two equations and get:
(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)
Now we have:
Vi/852mL = 315/452
Vi = (315/452)*852mL = 593.76mL
So when we expand the gas at constant pressure, we increase the temperature.
Answer:
395149.22 cubic inches.
Step-by-step explanation:
The volume of a tank with length (L), width (W) and height (H) is given by
V = LWH ........ (1)
Now, the interior dimensions of a tank are 82.5 inches long, 58.5 inches wide, and 81.875 inches tall.
So, L = 82.5 inches, W = 58.5 inches and H = 81.875 inches.
Therefore, V = (82.5 × 58.5 × 81.875) = 395149.22 cubic inches.
Hence, the approximate volume of the tank is 395149.22 cubic inches. (Answer)
