Please help me out lolll
2 answers:
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Answer:
Step-by-step explanation:
On a single roll of a pair of dice. When a pair of dice are rolled the possible outcomes are as follows:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
The number of outcomes that gives us 12 are (6,6). There is only one outcome that gives us sum 12.
Total outcomes = 36
Odd against favor =
Number of outcomes of getting sum 12 is 1
Number of outcomes of not getting sum 12 is 36-1= 35
odds against rolling a sum of 12=
Answer:
≈ -5.1857
≈ -5.4857
≈ 3.7262
Step-by-step explanation:
Rewrite the equation system as:
Now, write the system in its augmented matrix form:
applying row reduction process to its associated augmented matrix:
Swap R1 and R3, and then Swap R1 and R2:
R3+2R1
3R2+2R1
15R3+20R2
Now we have a simplified system:
From (3):
(4)
Replacing (4) in (2)
(5)
Finally replacing (5) and (4) in (1)