$\bf 12,\underline{351}\impliedby \textit{3 hundreds, and 51 units, let's round that}
\\\\\\
\begin{array}{llll}
300----- 50-----400\\
\qquad \qquad \uparrow\qquad \qquad \qquad \uparrow \\

\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
300
\end{array}\quad
\begin{array}{llll}
anything\ here\\
rounds\ up\ to\\
400
\end{array}
\end{array}
\\\\\\
\textit{therefore, the hundreds value of 300, the 51 tips it over to 400}
\\\\\\
12,\underline{400}$

3 0

3 years ago

Read 2 more answers

If x>2,then x2-x-6/x2-4=

statuscvo [17]

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

6 0

3 years ago