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alexgriva [62]
4 years ago
8

Order of operations for (6+25-7)÷6

Mathematics
2 answers:
Lorico [155]4 years ago
8 0

You do parentheses first and as long as it's just adding and subtracting you work from left to right.

6+25=31, then 31-7=24, then 24/6=4

So your answer is 4.

Pie4 years ago
7 0

the answer is 4

because: 6 + 25 = 31 - 7 = 24 ÷ 6 = 4


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Tell me the answer please. Give me a short answer and a step-by-step explanation.
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Answer:

A) 100 + 5x = y

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Step-by-step explanation:

100 is the amount Andre started with and 5x is the 5 he adds each week

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4 years ago
Triangle ABC is similar to triangle DEF . The length of AC is 10 cm. The length of BC is 15 cm. The length of DF is 6 cm.
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Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
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