Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

6 0

2 occurred 3times

$\\ \sf\longmapsto S=6\times 3=18$

$\\ \sf\longmapsto |S|=18$

Now

$\\ \sf\longmapsto E=No\:of\:times\: 2\:occured$

$\\ \sf\longmapsto |E|=3$

we know

$\boxed{\sf P(E)=\dfrac{|E|}{|S|}}$

$\\ \sf\longmapsto P(E)=\dfrac{3}{18}$

$\\ \sf\longmapsto P(E)=\dfrac{1}{6}$

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3 years ago

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Yes it is a function

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3 years ago

CORRECT GETS BRAINLIEST

Dmitrij [34]

C. 2/3 is the correct answer. I worked this question out and that is what I got! I hope you have a nice day! (mark as brainliest!)

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3 years ago