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3 years ago

$5,000 multiplyed by $150 multiplyed by $2500 multiplyed by 3%

Chemistry

2 answers:

irga5000 [103]3 years ago

7 0

Answer: 56250000

Explanation:

just multiply the first 3 numbers then you multiply it by 3%

ikadub [295]3 years ago

6 0

Answer:

I am not sure but I will say 5625

Explanation:

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Sveta_85 [38]

C, Have varying solubilities

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3 years ago

How would you know that an organization is a cooperative?

Sedbober [7]

Answer: A cooperative is a private business organization that is owned and controlled by the people who use its products, supplies or services. Although cooperatives vary in type and membership size, all were formed to meet the specific objectives of members, and are structured to adapt to member's changing needs. hope this helps. Can u give me brainliest

Explanation:

7 0

3 years ago

A 50.0 mL sample of a 0.200 M aqueous solution of Na3PO4 was added to 50.0 mL of a 0.100 M aqueous solution of BaCl2. The mixtur

sukhopar [10]

Answer:

1.02 grams

Explanation:

The reaction between Na₃PO₄ and BaCl₂ is:

2Na₃PO₄(aq) + 3BaCl₂(aq) → Ba₃(PO₄)₂(s) + 6NaCl(aq)

We need to find the number of moles of Na₃PO₄ and BaCl₂:

$n_{Na_{3}PO_{4}} = C*V = 0.200 M*0.050 L = 0.01 moles$

$n_{BaCl_{2}} = C*V = 0.100 M*0.050 L = 0.005 moles$

Now, we need to find the limiting reactant:

$n_{Na_{3}PO_{4}} = \frac{2}{3}*0.005 moles = 0.0033 moles$

We have that it is needed 0.0033 moles of Na₃PO₄ to react with BaCl₂ and we have 0.01 moles of Na₃PO₄, so the limiting reactant is BaCl₂.

The number of moles of Ba₃(PO₄)₂ is:

$n_{Ba_{3}(PO_{4})_{2}} = \frac{0.005}{3} = 0.0017 moles$

Finally, the mass of Ba₃(PO₄)₂ is:

$m = n_{Ba_{3}(PO_{4})_{2}}*M = 0.0017 moles*601.93 g/mol = 1.02 g$

Therefore, should be obtained 1.02 grams of the precipitate.

I hope it helps you!

3 0

3 years ago

Chloroform has a density of 1.5 g/ml. What the mass of 10.0 ml of Chloroform?

anzhelika [568]

Volume=10ml
Density=1.5g/ml

$\boxed{\sf Density=\dfrac{Mass}{Volume}}$

$\\ \sf\longmapsto Mass=Density\times Volume$

$\\ \sf\longmapsto Mass=1.5(10)$

$\\ \sf\longmapsto Mass=15g$

6 0

3 years ago

Please help me with this question number 22

hjlf

If I remember correctly 1 Cal (capital C) is equal to 1000 cal (lower case c) where Cal is used in nutrition since 1 cal is actually relatively small. If I am write about that, the answer should be 138Cal (nutritional calories) equals 138000cal. Therefore I think the answer is 138000cal.

I hope this helps. Let me know in the comments if anything is unclear.

6 0

3 years ago

$5,000 multiplyed by $150 multiplyed by $2500 multiplyed by 3%​

$5,000 multiplyed by $150 multiplyed by $2500 multiplyed by 3%