Answer:
Step-by-step explanation:
Let y(t) be the amount of salt in the tank after time t.
(A) Incoming rate = 0 (due to Pure water having no salt)
(B) Mixed solution comes out at 150 L/min. Initially the tank has 15,000 L of brine with 24 kg of salt.
concentration of salt at time t = y(t) / 15000 kg/L
Outgoing rate = y(t)/15000 * 150 = y(t) / 100
(C) we know that,


Separate variable and integrate



![y= Ce^{\frac{-t}{100} }\ [C=e^{D} ]](https://tex.z-dn.net/?f=y%3D%20Ce%5E%7B%5Cfrac%7B-t%7D%7B100%7D%20%7D%5C%20%20%5BC%3De%5E%7BD%7D%20%5D)
At t= 0 , y(0) = 24 kg

C= 24
(D) Therefore, the amount of salt in the tank after time t :

The product of the function is 2x^2+ 5x - 3
We are to find the product of the functions x + 3 and 2x -1
Taking the product:
f(x)g(x) = (x+3)(2x -1)
f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)
f(x)g(x) = 2x^2 - x + 6x - 3
f(x)g(x) = 2x^2+ 5x - 3
Hence the product of the function is 2x^2+ 5x - 3
Learn more on product of functions here: brainly.com/question/25638609
Answer:
- 
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 5x - 2 ← is in slope- intercept form
with slope m = 5
Given a line with slope m then the slope of a line perpendicular to it is
= -
= - 