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Kruka [31]
3 years ago
13

The figure below has one base

Mathematics
1 answer:
Tanya [424]3 years ago
6 0

Answer: B

Total surface area = 320 m^2

Step-by-step explanation:

The figure is a combination of a cuboid and pyramid.

The Surface Area of a Pyramid When all side faces are the same:

[Base Area] + 1/2 × Perimeter × [Slant Length]

Let us use pythagorean theorem to calculate the slant length

Slant length = root(6^2 + 4^2)

Slant length = 7.2 m

Base area = 8 × 8 = 64 m^2

Perimeter = 8+8+8+8 = 32 m

Surface area of the pyramid will be

= 64 + ( 1/2 × 32 ) × 7.2

= 64 + 16 × 7.2

= 64 + 115.4

= 179.4 m^2

The surface area of the cuboid will be

LB + LH + BH = 8×8 + 8×5 + 8×5

= 64 + 40 + 40

= 144 m^2

Total surface area = 179.4 + 144

Total surface area = 323.4 m^2

= 320 m^2 to the nearest whole number.

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Vesnalui [34]

Penjelasan langkah demi langkah:

1)

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2) √32 +3√18-2√50

= √16*2 +3√9*2-2√25*2

= 4√2 + 3(3√2)-2(5√2)

= 4√2 + 9√2-10√2

= 13√2-10√2

= 3√2

3) 1000 ⅔×64⅙

 = (\sqrt[3]{1000}) ^2 \times (2^6)^{1/6}  \\= 10^2 \times 2\\= 100 \times 2\\= 200

4) 3/4+√2

3/4+\sqrt{2} \\= \frac{3+4\sqrt{2} }{4 }

5) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

6) 12/3+√3

= 4+√3

7) √1000—2√40

= 10 -2 (√4*10)

= 10-2(2√10)

= 10 - 4√10

8) 2- ¹+3-¹

= \frac{1}{2} + \frac{1}{3}\\ = \frac{3+2}{6}\\ = \frac{5}{6}

9)

\frac{5}{\sqrt{5} }\\ merasionalisasikan\\= \frac{5}{\sqrt{5} }\times \frac{\sqrt{5} }{\sqrt{5} }\\= \frac{5\sqrt{5} }{\sqrt{25} }\\= \frac{5\sqrt{5} }{5}\\ = \frac{\sqrt{5} }{1}

Jika pernyataannya opsional, penyebutnya adalah 1

10) 2√3×√18

= 2√3×√9*2

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= (2*3)(√3*√2)

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7 0
3 years ago
The perimeter of a triangle is 140 cm the length of the second side is twice the length of the first side the length of the thir
kykrilka [37]

Perimeter = 140

Side 1 = x

Side 2 = 2x

Side 3 = 3x - 10

x + 2x + 3x - 10 = 140

6x - 10 = 140

6x = 150

x = 25

Side 1 = 25 cm

Side 2 = 50 cm

Side 3 = 65 cm

Hope this helps!! :)

6 0
2 years ago
Read 2 more answers
Nter the equation of the line in slope-intercept form.<br><br> Slope is 6, and (1, 3)
kupik [55]

Answer:

The equation in the slope-intercept form will be:

y=6x-3

Step-by-step explanation:

Given

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As we know that the equation of a line in point-slope form is

y-y_1=m\left(x-x_1\right)

substituting the values m = 6 and point = (1, 3)

y-3=6\left(x-1\right)

Writing the equation in slope-intercept form

y=mx+b

where m is the slope, and b is the y-intercept

so the equation of the line in slope-intercept form becomes

y-3=6\left(x-1\right)

add 3 to both sides

y-3+3=6\left(x-1\right)+3

y=6x-3

Therefore, the equation in the slope-intercept form will be:

y=6x-3

6 0
3 years ago
A large cheese pizza costs $7.50. Each additional topping for the pizza costs $1.35. If the total bill for the pizza Sally order
konstantin123 [22]

Answer: She ordered 4 toppings.

Step-by-step explanation:

Given: Total cost of pizza  = $ 12.90

Cost of pizza =$7.50

Price per topping = $1.35

Let x = Number of toppings,

Total cost of pizza = (Cost of pizza) + (price per topping) × (Number of topping)  

12.90= 7.50+1.35x\\\\\Rightarrow\ 1.35x=12.90-7.50\\\\\Rightarrow\ 1.35x=5.4\\\\\Rightarrow\ x=\dfrac{5.4}{1.35}\\\\\Rightarrow\ x=\dfrac{540}{135}=4

hence, she ordered 4 toppings.

5 0
2 years ago
The volume of a right cylinder is V = πr2h. If we have an oblique cylinder, like in the figure, what is the volume of a cross-se
olchik [2.2K]
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.

First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.

I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.

Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.

Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).

Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.

Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.

Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
8 0
3 years ago
Read 2 more answers
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