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Kruka [31]
3 years ago
13

The figure below has one base

Mathematics
1 answer:
Tanya [424]3 years ago
6 0

Answer: B

Total surface area = 320 m^2

Step-by-step explanation:

The figure is a combination of a cuboid and pyramid.

The Surface Area of a Pyramid When all side faces are the same:

[Base Area] + 1/2 × Perimeter × [Slant Length]

Let us use pythagorean theorem to calculate the slant length

Slant length = root(6^2 + 4^2)

Slant length = 7.2 m

Base area = 8 × 8 = 64 m^2

Perimeter = 8+8+8+8 = 32 m

Surface area of the pyramid will be

= 64 + ( 1/2 × 32 ) × 7.2

= 64 + 16 × 7.2

= 64 + 115.4

= 179.4 m^2

The surface area of the cuboid will be

LB + LH + BH = 8×8 + 8×5 + 8×5

= 64 + 40 + 40

= 144 m^2

Total surface area = 179.4 + 144

Total surface area = 323.4 m^2

= 320 m^2 to the nearest whole number.

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In this problem, we have that:

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The length of arc AB is 9.12 mm:

We first calculate for the radius r of the circle using the equation
     r = c/(2 sin[theta/2]) 

     where c is the length of chord AB that is given as 9 millimeters
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To convert theta 32 degrees into radians:
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