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g100num [7]
3 years ago
8

A 50kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches

a velocity of 3m/s. What was the force acting on the mass?​
Physics
1 answer:
Marina CMI [18]3 years ago
3 0

Answer:

75N

Explanation:

a = v/t = 3/2

F = ma = 50(3/2) = 75

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The two factors that affect the electric force are the charges and the separation between the objects

Explanation:

The magnitude of the electrostatic force between two objects is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

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k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the charges of the two objects

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Answer:

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