55 Kg has a weight of 55x9.8= 539 N
That is equal to the Normal force.
The static friction = 0.19 x 539 = 102.4 N
Answer:
3600 J
Explanation:
According to given question
P(rated)=60w
V= 120
I =0.50 A
t=600 second
Now,
Energy can be calculated as :

Where,
V is voltage
I is current
t is time in second
Now,
Putting the all value in above equation E
So,

Therefore, 36000 J energy use up by light bulb