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3 years ago

true or false the speed of sound traveling through steel is much less than the speed of sound traveling through air

Physics

2 answers:

ValentinkaMS [17]3 years ago

5 0

True because steel is much heavier and will make the sound travel through it slower

Misha Larkins [42]3 years ago

4 0

This is false. Sound travels faster through steel. That is why you can see people in movies putting their ear on the railroads to see whether a train is coming. That is because they can't hear it through air, but the sound travels through the steel.

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Two resistors R1 = 6.7 Ω and R2 = 1.6 Ω are connected in parallel and a potential difference of ΔV = 12.0 V is imposed across th

Softa [21]

Answer:

I1 = 1.8A

I2 = 7.5A

I = 9.3A

Explanation:

From the principle of basic electricity, when resistors are connected in parallel, the potential difference across them is the same but the current may vary depending on the value of the resistors.

Firstly we calculate the equivalent resistance in the circuit

1/R = 1/R1 + 1/R2

1/R = 1/6.7 + 1/1.6 = 0.774

R = 1/0.774 = 1.292Ω

Now let's calculate the total current flowing through the circuit (I)

V=IR

12=I × 1.292

I = 12/1.292 = 9.3A

The current flowing across R1 (I1) is calculated as

V = I1 × R1

12 = I1 × 6.7

I1 = 12/6.7

I1 = 1.8A

= 12/1.292 = 9.3A

The current flowing across R1 (I1) is calculated as

V = I1 × R1

12 = I1 × 6.7

I1 = 12/6.7

I1 = 1.8A

The current flowing across R2 is (I2) is calculated as

V = I2 × R2

12 = I2 × 1.6

I2 = 12/1.6

I2 = 7.5A

Confirming our overall current value

I1 + I2 = I

1.8A + 7.5A = 9.3A

6 0

3 years ago

Which type of employee would most likely spend the majority of work time in a vehicle? O a Corrections Officer at a jail O a Dis

dsp73

Answer:

Paramedic

Explanation:

They will be on the move the whole time

8 0

3 years ago

Read 2 more answers

Identify and describe one past geologic process that formed copper ore deposits.

r-ruslan [8.4K]

Answer:

tornado and land

Explanation:

7 0

3 years ago

Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the

ivann1987 [24]

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

$x=vt$ (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s

You solve the equation (1) for t:

$t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s$

The time on which the bat hears the echo is twice the value of t, that is:

$t'=2(0.125s)=0.250s$

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s

6 0

3 years ago

I will pick the branliest if answered these questions.

Bond [772]

n₁ = index of refraction of diamond = 2.4

n₂ = index of refraction of water = 1.33

θ₁ = angle of incidence = 24 deg

θ₂ = angle of refraction = ?

using snell's law

n₁ Sinθ₁ = n₂ Sinθ₂

inserting the values

(2.4) Sin24 = (1.33) Sinθ₂

θ₂ = 47.22 deg

c = specific heat = 4.18

m = mass of water = 3.5 kg

ΔT = change in temperature = 55 - 25 = 30 C

Q = heat taken

heat taken is given as

Q = m c ΔT

inserting the values

Q = (3.5) (4.18) (30)

Q = 439 J

n = number of moles = 1

m = molar mass = 0.0399 kg

T = temperature = 27 K

v = average velocity

average velocity is given as

v = sqrt(3RT/m)

v = sqrt(3 x 8.314 x 275/0.0399)

v = 414.6m/s

n = number of moles = 2

T = temperature = 35 C = 35 + 273 K = 308 K

U = internal energy

internal energy is given as

U = 2.5 n RT

U = 2.5 (2) (8.314) (308

U = 1.28 × 10⁴ J

F₁ = 3300 N

F₂ = ?

A₁ = 0.060 m²

A₂ = 0.18 m²

Using pascal's law

F₁/A₁ = F₂/A₂

3300/0.060 = F₂/0.18

F₂ = 9900 N

R = resistance of each resistance in series = 10 ohm

R' = equivalent resistance in series

equivalent resistance is given as

R' = 3 R

R' = 3 x 10

R' = 30 ohm

R = resistance of each resistance in parallel = 10 ohm

R'' = equivalent resistance in parallel

equivalent resistance is given as

R'' = R/3

R'' = 10/3

R'' = 3.3 ohm

for series circuit

R' = equivalent resistance in series = 30 ohm

V = Voltage applied = 60 Volts

i' = current in each resistor in series

current in each resistor in series is given as

I' = V/R'

i' = 60/30

i' = 2 A

for parallel circuit :

i = current in each resistor = V/R = 60/10 = 6 A

6 0

4 years ago

Read 2 more answers