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Wittaler [7]
3 years ago
8

A student's backpack has a mass of 9.6 kg. The student applies a force of 94.08 N [up] while walking through 1.4 km [E] to get t

o school. Calculate the work done by the student on the backpack
Physics
1 answer:
Evgesh-ka [11]3 years ago
8 0

The student does zero work on the backpack because the upward force applied by the student is acting <em>perpendicular</em> to the backpack's displacement parallel to the ground.

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Mega rayquaza and zygarde 100% form vs lunala, solgaleo, and red's mega charizard
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That right there is what caused the world to end my friend

Explanation:

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3 years ago
Consider massive gliders that slide friction-free along a horizontal air track. Glider A has a mass of 1 kg, a speed of 1 m/s, a
mamaluj [8]

Answer:

0.167m/s

Explanation:

According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.

Given momentum = Maas × velocity.

Momentum of glider A = 1kg×1m/s

Momentum of glider = 1kgm/s

Momentum of glider B = 5kg × 0m/s

The initial velocity of glider B is zero since it is at rest.

Momentum of glider B = 0kgm/s

Momentum of the bodies after collision = (mA+mB)v where;

mA and mB are the masses of the gliders

v is their common velocity after collision.

Momentum = (1+5)v

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1kgm/s + 0kgm/s = 6v

1 =6v

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3 years ago
Two 100kg bumper cars are moving towards eachother in oppisite directions. Car A is moving at 8 m/s and Car B at -10 m/s when th
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Answer:

-10 m/s

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By momentum conservation equation

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C. It will decrease


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4 years ago
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Answer:

c

Explanation:

simple

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3 years ago
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