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shusha [124]
2 years ago
7

Ayuda plisss, es urgente

Physics
1 answer:
kramer2 years ago
8 0

(Lo siento si mi español es malo, no es mi primera lengua )

1. velocidad media = desplazamiento/tiempo

desplazamiento = 0 porque el athelete vuelve al punto inicial en un círculo

velocidad media = desplazamiento/tiempo = 0/10 = 0

2. la distancia entre A y B es 5 cm porque

a^2 + b^2 = c^2 (el teorema de Pitágoras) así:

rapidez media = distancia/tiempo = 5/5 = 1 cm/s o 0.01 m/s

y yo no se cómo hacer 3-5 :( lo siento

3. Creo que es dos triángulo s AB y CD menos la línea de fondo

5. Creo que es E + F porque B y D b y d cancelarse el uno al otro y C y C tambien pero no lo sé con seguridad.

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Answer with Step-by -step explanation:

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b.\mid A\mid=46 m

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y-Component of vector A=A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64

Magnitude of vector B=86 m

The vector B makes angle with positive x- axis=x'=42^{\circ}

x-component of vector B=B_x=86cos42=63.64

y-Component of vector B=B_y=86sin42=57.62

Vector A=A_xi+A_yj=43.24i-15.64j

Vector B=B_xi+B_yj=63.64i+57.62j

Vector C=A+B

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C=43.24i-15.64j+63.64i+57.62j

C=106.88i+41.98j

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x = 0

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v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

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now we have

a = -\frac{\pi^2}{16}*\sqrt2

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<em>so above is the instantaneous accelerations</em>

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