The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
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Answer:
35 mi²
Step-by-step explanation:
Let's subdivide the figure, as shown.
The lower part is a rectangle whose area is (5 mi)(18 mi) = 90 mi².
The upper part is a trapezoid whose area is found by averaging the length and multiplying the result by the width (8 mi - 5 mi), or 3 mi.
Area of trapezoid:
12 mi + 18 mi
------------------------ = 15 mi Width of trapezoid = 3 mi
2
Thus, the area of the trapezoid is (3 mi)(15 mi) = 45 mi²
and the total area of the entire figure is
45 mi² + 90 mi² = 135 mi²
Answer:
Matched pairs design
Step-by-step explanation:
Looking at the options;
-It's not a completely randomized design because a randomized design will assign all individuals to a group which in this case it doesn't.
- It's not a randomized block design because randomized block design will group the subjects in question into 2 or more blocks which have a common characteristic and will then randomly assign subjects in each of the blocks.
-It's a matched pair because every individual/subject undergoes measurements both before and after being treated with the drugs.
Thus, the correct option is matched pairs design.