Answer:
We can conclude that there is significant evidence that Northwood residents owned their homes for a longer period of time compare to residents in the Southlake area
Step-by-step explanation:
H0 : μ1 = μ2
H1 : μ1 < μ2
Given :
n1 = 14 ; n2 = 28
x1 = 7.4 ; x2 = 9.1
s1 = 2.3 ; s2 = 2.9
α = 0.05
Test statistic :
(x1-x2) ÷ sqrt[(((n1-1)*s1² + (n2-1)*s2²) ÷ df) * (1/n1+1/n2)]
(7.4 - 9.1) ÷ sqrt[(((13*2.3^2) + (27*2.9^2)) ÷ 40) * (1/14 + 1/28)]
t = -1.7 ÷ sqrt[((68.77 + 227.07) / 40) * 0.1071428]
t = -1.7 ÷ sqrt(0.7924281488)
t = - 1.7 ÷ 0.8901843
t = - 1.909
t = - 1.91
The Pvalue :
P(t < - 1.91) = 0.028067
At α = 0.05 ;
Pvalue < α ; We reject the Null
We can conclude that there is significant evidence that Northwood residents owned their homes for a longer period of time compare to residents in the Southlake area
The
value is multiplied by 3 when n increases by 1. The only expression that does that is the one that has 3 as the base of the exponential term.
The appropriate selection is ...
![a_n=\dfrac{1}{3}(3)^{n-1}](https://tex.z-dn.net/?f=a_n%3D%5Cdfrac%7B1%7D%7B3%7D%283%29%5E%7Bn-1%7D)
10(.5x + 6) = 8
.5 can also be exchanged for a 1/2
To solve this, you can distribute the 10 and then subtract and divide, like so:
5x + 60 = 8
5x = -52
x = -10.4