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geniusboy [140]
2 years ago
9

Use the graph that shows the solution to f(x)=g(x).

Mathematics
1 answer:
Charra [1.4K]2 years ago
4 0

The solution to the system of equations is given as follows:

x = 1 and x = 3.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the two equations are:

\frac{1}{x - 2} = x - 2

Applying cross multiplication:

(x - 2)(x - 2) = 1

x² - 4x + 4 = 1

x² - 4x + 3 = 0

(x - 1)(x - 3) = 0

Hence the solutions are:

  • x - 1 = 0 -> x = 1.
  • x - 3 = 0 -> x = 3.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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Match each pair of points to the equation of the line that is parallel to the line passing through the pointsB(5,2) and C(7,-5)Y
a_sh-v [17]

we will select each points and find equation of line

option-A:

points are B(5,2) and C(7,-5)

x1=5,y1=2 , x2=7 , y2=-5

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-5-2}{7-5}

m=-3.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=-3.5(x-5)

y=\frac{-7}{2}x+\frac{39}{2}...........Answer

option-B:

points are D(11,6) and E(5,9)

x1=11,y1=6 , x2=5 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-6}{5-11}

m=-0.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-6=-0.5(x-11)

y=\frac{-1}{2}x+\frac{23}{2}...........Answer

option-C:

points are F(-7,12) and G(3,-8)

x1=-7,y1=12 , x2=3 , y2=-8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-8-12}{3+7}

m=-2

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-12=-2(x+7)

y=-2x-2...........Answer

option-D:

points are H(4,4) and I(8,9)

x1=4,y1=4 , x2=8 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-4}{8-4}

m=1.25

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-4=1.25(x-4)

y=\frac{5}{4}x-1...........Answer

option-E:

points are J(7,2) and K(-9,8)

x1=7,y1=2 , x2=-9 , y2=8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{8-2}{-9-7}

m=-\frac{3}{8}

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=\frac{3}{8}(x-7)

y=\frac{3}{8}x-\frac{5}{8}...........Answer

option-F:

points are L(5,-7) and M(4,-12)

x1=5,y1=-7 , x2=4 , y2=-12

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-12+7}{4-5}

m=5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+7=5(x-5)

y=5x-32...........Answer



7 0
3 years ago
Read 2 more answers
If v1 = (2,-5) and v2 = (4,-3), then the angle between the two vectors is _________. Round your answer to two decimal places.
siniylev [52]
The angle between two vectors is given by:
 cos (x) = (v1.v2) / (lv1l * lv2l)
 We have then:
 v1.v2 = (2, -5). (4, -3)
 v1.v2 = (2 * 4) + (-5 * (- 3))
 v1.v2 = 8 + 15
 v1.v2 = 23
 We look for the vector module:
 lv1l = root ((2) ^ 2 + (-5) ^ 2)
 lv1l = 5.385164807
 lv2l = root ((4) ^ 2 + (-3) ^ 2)
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 Substituting values:
 cos (x) = (23) / ((5.385164807) * (5))
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x = 31.33 degrees
3 0
3 years ago
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kolezko [41]

Answer:

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Step-by-step explanation:

The topic is students' weekly exercise so the question has to be about that. also, there are up to 7 days worth of data and there a 7 days in a week. so she most likely asked the question, "How many days do you exercise in a week?".

4 0
3 years ago
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Verdich [7]

Answer:

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Step-by-step explanation:

just like 100 is ten times greater than 10.

4 0
3 years ago
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Svetlanka [38]
A = p(1 + rt)
A/p = 1 + rt
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