Question

Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2

Answer 1

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term  given as 8 and

d=  common difference given as 2

Therefore  We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18