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3 years ago

Write the first 6 terms of the arithmetic sequence whose first term is 8 and has a common difference of 2

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Answer: The first 6 terms are = 8, 10, 12,14,16,18

Step-by-step explanation:

The NTH term of an Arithmetic Sequence is given as

an = a1 + (n - 1 ) d

where a1 = First term given as 8 and

d= common difference given as 2

Therefore We have that

the first term

an = a1 + (n - 1 ) d = 8+(1-1) 2

a1= 8

second term=

an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2

= 8+ 2(1) = 10

3rd term

an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2

= 8+ 2(2)= 8 + 4=12

4th term

an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2

= 8+ 2(3)= 8+6=14

5th term

an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2

= 8+ 2(4)=8+ 8=16

6th term

an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2

= 8+ 2(5)=8 +10 =18

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3 years ago

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nadya68 [22]

Answer:

BAC=BDC(BDX)=30°

Step-by-step explanation:

We know that BD=OD.

But OD=OB= Radius of the circle.

Therefore

BD=OD=OB

BDO is equilateral triangle.

Angle DBO= 60°

Now let us take the intersecting point of CD and AB as X.

In triangle BDX,

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Therefore,

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mrs_skeptik [129]

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3 years ago

What is the volume of a sphere with a radius of 49.5 in, rounded to the nearest tenth of a cubic inch?

NeX [460]

Answer:

Below

Step-by-step explanation:

To find the volume of a sphere you can use this formula!

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Plugging in the values....

V = 4/3π(49.5)^3

V = 5.08047 × 10^5

V = 5.1 x 10^5 in^3

If you wanted to write this is standard form it would be

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3 years ago

Find the value of k so that the remainder is 1 when x^3+5x^2+kx-8 is divided by (x-3) K=

Brut [27]

By the remainder theorem, the remainder upon dividing $x^3+5x^2+kx-8$ by $x-3$ is given by the value of this expression when x = 3 :

$3^3 + 5\cdot3^2 + 3k - 8 = 1$

Solve for k :

$27 + 45 + 3k - 8 = 1 \\\\ 3k = -63 \\\\ \boxed{k = -21}$

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2 years ago