Median, upper quartile, and maximum are all incorrect
Answer:
That x is any number bigger that 5 so 6 plus
Step-by-step explanation:
Answer:
It is irrational because it can not be represented as a fraction of two integers
Step-by-step explanation:
Given


![H = \sqrt[3]5](https://tex.z-dn.net/?f=H%20%3D%20%5Csqrt%5B3%5D5)
Required
Why is the area irrational?
First, we need to calculate the area

![Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%283.6%20%2B%2012%5Cfrac%7B1%7D%7B3%7D%29%20%2A%20%5Csqrt%5B3%5D5)







<em>It is irrational because it can not be represented as a fraction of two integers</em>
Answer:
6
Step-by-step explanation:
root the 216 as it is a cube
:edge *edge *edge =volume
Since all edges are the same, just root it