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4 years ago

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True or False: On the least-squares regression line, the point (x,y) always has a

1 answer:

777dan777 [17]4 years ago

3 0

I think true. Hope this helps!

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Indicate If these triangles are SSS SAS SAA ASA HL or none

mrs_skeptik [129]

The answer is SAS
Hope this helps......

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3 years ago

Read 2 more answers

Delia relative long jump length was recorded as 0. What does this mean

Deffense [45]

<span>When we say about an object relative to something, this only means that we are comparing an object’s characteristic to that of our reference. So in this case, I think we are referencing Delia’s jump to someone else. Say our reference has a long jump length of 5 meters, since Delia’s relative long jump length is 0, this means that relative to the reference there is no difference. Therefore, Delia’s jump length is also 5 meters.</span>

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4 years ago

Match each word with the correct part of the expression.

ziro4ka [17]

Expression: 5x + 12

Coefficients (The number directly next to the variable): 5

Variable (A letter that stands for a unknown number): x

Term (A single mathematical expression): 5x , 12

Constant (A term that has no attached variables): 12

7 0

2 years ago

HELP I WILL GIVE BRAINLIEST I MEED THIS ASAP

Vera_Pavlovna [14]

What is the question?

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4 years ago

If f(x) = 3x2 − 8x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints.

denis23 [38]

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

$r_i=0+\dfrac i2=\dfrac i2$

with $1\le i\le6$ .

We approximate the integral of $f(x)$ on the interval [0, 3] by the Riemann sum,

$\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i$

$\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)$

$\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)$

$\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i$

Recall the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

Then the value of the integral is approximately

$\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875$

Compare to the exact value of the integral, -9.

7 0

3 years ago