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3 years ago

14

If a cat can run 152 yards in 5 minutes how far can the cat run per minute

1 answer:

Ainat [17]3 years ago

6 0

Answer:

30.4

Step-by-step explanation:

152/5=30.4

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Why is estimation useful when finding actual products and solving real-world problems?

Molodets [167]

It's Cause We Study Real-World-Problems Without Education We wouldn't learn anything so its good to study independently so our brains can grow!

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3 years ago

Read 2 more answers

An auto transport truck holds 12 cars. A car dealer plans to bring in 1,006 new cars in June and July. If an auto transport truc

marin [14]

To find the number of full trucks we can do 1006 / 12. This gives us 83.8333. That is, 83 full trucks and a bit left over.
The bit left over is the answer to the second part, the last truck. 0.8333 is the same as 10/12, so the last truck will have 10 cars in it. If we didn’t know that fraction, we could find the answer by saying 12x83 = 996. 1006 - 996 = 10.

So the final answer is: 83 full trucks and 10 cars in the last truck.

3 0

3 years ago

Dan buys a car for £2200.

KatRina [158]

Answer:

The worth of the car after 6 years is £2,134.82

Step-by-step explanation:

The amount at which Dan buys the car, PV = £2200

The rate at which the car depreciates, r = -0.5%

The car's worth, 'FV', in 6 years is given as follows;

$FV = PV \cdot \left ( 1 + \dfrac{r}{100} \right )^n$

Where;

r = The depreciation rate (negative) = -0.5%

FV = The future value of the asset

PV = The present value pf the asset = £2200

n = The number of years (depreciating) = 6

By plugging in the values, we get;

$FV = 2200 \times \left ( 1 + \dfrac{-0.5}{100} \right )^6 \approx 2,134.82$

The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))

8 0

3 years ago

In the circle below, DB = 22 cm, and m<DBC = 60°. Find BC. Ignore my handwriting.

Karo-lina-s [1.5K]

Answer:

$BC=11\ cm$

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

$m\angle DBC=\frac{1}{2}[arc\ DC]$

substitute the values

$60\°=\frac{1}{2}[arc\ DC]$

$120\°=arc\ DC$

$arc\ DC=120\°$

step 2

Find the measure of arc BC

we know that

$arc\ DC+arc\ BC=180\°$ ----> because the diameter BD divide the circle into two equal parts

$120\°+arc\ BC=180\°$

$arc\ BC=180\°-120\°=60\°$

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

$m\angle BDC=\frac{1}{2}[arc\ BC]$

substitute the values

$m\angle BDC=\frac{1}{2}[60\°]$

$m\angle BDC=30\°$

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

$sin(\angle BDC)=BC/BD$

$BC=(BD)sin(\angle BDC)$

substitute the values

$BC=(22)sin(30\°)=11\ cm$

6 0

3 years ago

Cindy's job is to check computer printers for defects. Out of 420 printers she has to check, only 3 of the first 84 have been de

kaheart [24]

46% printers are defective = 106 printers defective

5 0

4 years ago