The general or standard form of a parabola is
(y-k) = a(x+h)^2
h,k are the intersection points of parabola
Intersection points are where y= 0, or x=0
itsnorigin at (,0,0)that means h=0, k=0
it passes through points (-1,2) and (1,2)
So then
y= ax^2 , 2 = a (-1)^2
this means a= 2
Then results standard form equation
Y = 2• X^2
Answer:
-7
Step-by-step explanation:
Hope it helped!
Yes it's A cos that's the correct answer
X+y= -12
xy=8
y=8/x
x+8/x=-12
x^2+12x+8=0
This has no integral
I’m pretty sure it would be just E and F
