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larisa86 [58]
3 years ago
15

Give the function f(x) = x + 7find f(5)​

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Answer:

f(5) = 12

Step-by-step explanation:

f(x) = x +7

f(5) = (5) + 7

f(5) = 12

Hope this helps and I hope u have an Amazing day!!

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Find the midpoint of the segment with the following endpoints.<br> (8,5) and (0, -1)
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Answer:

(4,2)

Step-by-step explanation:

Midpoint =\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(8,\:5\right),\:\\\left(x_2,\:y_2\right)=\left(0,\:-1\right)\\\\=\left(\frac{0+8}{2},\:\frac{-1+5}{2}\right)\\\\= (\frac{8}{2} , \frac{4}{2} )\\\\Simplify\\=\left(4,\:2\right)

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3 years ago
If p q r is prime numbers such that pq+r=73, what is the least possible value of p+q+r
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The answer to this question would be: p+q+r = 2 + 17 + 39= 58

In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number. 

There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73

The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39

p+q+r = 2 + 17 + 39= 58
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I hope this helps you

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