The average speed of the truck is calculated by dividing the total distance traveled in a span of the total time given. From the given above, the total distance traveled is
total distance = 203 mi + 243 mi = 446 mi
and the total time it took for the whole trip is
total time = 3.5 h + 4.5 h = 8 h
The average speed is therefore,
average speed = 446 mi/8 h = 55.75 mi/h
Thus, the answer is letter A.
Answer:
hbw ygav
Step-by-step explanation:
Answer:
85/100
Step-by-step explanation:
There are only 2 numbers after the decimal point which means that is 0/100. You would get 85/100 and you can't simplify more than that.
Hope This Helps :)
Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.
Answer:
First of all, he have to find out what 0.5% of the students is.
Second of all, find out what 0.5 of 100 is. 100 divided by 0.5 is 200.
Third of all, divide 200 from 639. This equals 3.195
Since it is asking about how many, I would go with about 3. After all, you can't have have half of a person, so the decimals shouldn't be added.
Step-by-step explanation: