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FrozenT [24]
2 years ago
6

Need help. pls help. i suck at math. math is a no no for me. help me pls.​

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
5 0

Answer:

A5#A

Step-by-step explanation:

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Sea level is considered to be 0 feet. A probe released at sea level dropped at a constant rate for 3.25 minutes, reaching an ele
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d = r * t

d/t = r

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Common factor

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PLSS I NEED HELP ASAP BECAUSE ITS DUE SOON
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D. 10 x 62

If one row needs 62 bricks and there's 10 rows, you multiply them to get how many bricks nick needs
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The probability of rain on any given day is 2/3 . What is the probability of at most one day of rain during the next three days?
MArishka [77]

Answer:

\frac{7}{27}

Step-by-step explanation:

Let the event of raining on a day be success.

Then probability of success, p=\frac{2}{3}

So, probability of failure is not raining on a day and is given as,

q=1-p=1-\frac{2}{3}=\frac{3-2}{3}=\frac{1}{3}

Now, number of days to check the probability of rain, n=3

Now, probability of raining at most one day means number of success is either 0 or 1.

Using Bernoulli's distribution for X=0,1

P(X=0\textrm{ or }X=1)=_{0}^{3}\textrm{C}p^{0}q^{3-0}+_{1}^{3}\textrm{C}p^{1}q^{3-1}\\\\P(X=0\textrm{ or }X=1)=(\frac{1}{3})^{3}+3(\frac{2}{3})^{1}(\frac{1}{3})^{2}\\\\P(X=0\textrm{ or }X=1)=\frac{1}{27}+\frac{2}{9}\\\\P(X=0\textrm{ or }X=1)=\frac{1}{27}+\frac{6}{27}\\\\P(X=0\textrm{ or }X=1)=\frac{1+6}{27}=\frac{7}{27}

Therefore, the probability of at most one day of rain during the next three days is \frac{7}{27}

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3 years ago
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