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aleksandrvk [35]
3 years ago
8

The function f(x) = - (x + 5) * (x + 1) shown What is the range of the function ? 10 all real numbers loss than or equal to all

roal numbers less than or equal to -3 all real numbers groater or equal to 4 numbors greater than or equal to -6
Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Given:

The function is:

f(x)=-(x+5)(x+1)

To find:

The range of the function.

Solution:

We have,

f(x)=-(x+5)(x+1)

It can be written as:

f(x)=-(x^2+x+5x+5)

f(x)=-(x^2+6x+5)

Add and subtract square of half of coefficient of x, i.e., \left(\dfrac{6}{2}\right)^2=9.

f(x)=-(x^2+6x+9-9+5)

f(x)=-(x^2+2(x)(3)+3^2-4)

f(x)=-(x^2+2(x)(3)+3^2)+4

f(x)=-(x+3)^2+4

On comparing this equation with f(x)=a(x-h)^2+k, we get

a=-1, it means the graph of the function is a downward parabola and the vertex is the point of maxima.

h=-3

k=4

The vertex of the function is (-3,4). So, the value of the function cannot be greater than 4.

Therefore, the range of the function is all real numbers less than or equal to 4.

Note: All options are incorrect.

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Answer:

R(x,y) = (0.8,-1.2)

Step-by-step explanation:

The coordinates of QS are:

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The ratio is represented as:

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Required

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The coordinates of R is calculated by:

R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})

Substitute values for m, n, x's and y's

R(x,y) = (\frac{2 * 5 + 3 * -2}{2+3},\frac{2*6 + 3*-6}{2+3})

R(x,y) = (\frac{4}{5},\frac{-6}{5})

R(x,y) = (0.8,-1.2)

<em>None of the options is correct</em>

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