Answer:
156.24N
Explanation:
From the data above;
Mass = 23g = 0.023kg
V = 88m/s
Kinetic energy = ½mv²
K.e = ½* 0.023 * 88²
K.E = 89.056J
The force required to accelerate the arrow to that speed and energy in 0.57m
Using equation of motion;
V² = U² + 2as
But U =0
V² = 2as
a = v²/2s
a = 88² / (2*0.57)
a = 6792.98m/s²
The force (F) that accelerates the arrow with that velocity = ?
F = M*a
F = 0.023 * 6792.98
F = 156.24N
Answer:
False. It is propelled but projectile is a specific term denoting air friction only after release of energy.
The value of v; initial velocity is determined as, v = h/t + gt.
<h3>What is initial velocity of an object?</h3>
The initial velocity of an object is the velocity of the object before the effect of acceleration, which causes the change of velocity.
h = vt - gt²
to solve for v (the initial velocity) we will make v the subject of the formula.
h + gt² = vt
divide both sides of the equation by t
h/t + gt = v
Thus, the value of v; initial velocity is determined as, v = h/t + gt.
Learn more about initial velocity here: brainly.com/question/19365526
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Answer:75 percent
Explanation:so in order tro fin d thge efficiency i used the forumla ,efficency=useful output energy/input energyx100%,in order to use this formula i needed the output,which i found by subtracting the input energy with wasted energy,that gave me the output,and after founding the output,i put that into the formula,
output energy=input energy - wasted energy
output energy=6000j-1500j
output energy=4500
put that into the formula
efficiency =output energy/input enrgy x100%
efficiency=4500/6000 multiplied by 100%
efficiency=0.75x100%
efficiency=75%
Answer: 5 m/s North
Explanation:
Velocity = Momentum/Mass
Velocity = 225 kg*m/s/45kg
Velocity = 5 m/s North
