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eduard
3 years ago
14

Sound waves are created by _____.

Physics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

C. undulating displacement of air molecules caused by pressure changes.

Explanation:

Sound is a mechanical wave arising from the movement back and forth of the media objects through which the sound wave travels.If a sound wave moves through air from left to right, then particles of air will move both to the right and to the left as the sound wave's energy passes through it.

The sound wave is formed by air molecules that are displaced due to pressure changes.

Therefore the answer is C.

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If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 55.0 m/s in the opposite directi
Naddik [55]

Answer:

14.79 kgm/s

Explanation:

Data provided in the question

Let us assume the mass of baseball =  m = 0.145 kg

The Initial velocity of pitched ball = v_i = 47 m/s

Final velocity of batted ball in the opposite direction = v_f= -55m/s

Based on the above information, the change in momentum is

\Delta P = m(v_f -v_i)

=  0.145 kg(-55m/s - 47m/s)    

= 14.79 kgm/s

Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s

3 0
3 years ago
What is the potential energy of a 2-kilogram potted plant that is on a 1 meter-high plant stand?
alina1380 [7]


Ep=mgh

In your case it's Ep = 2*9,8*1=19,6 J

5 0
3 years ago
1. Answer the question below. Use the rubric in the materials for help if needed.
exis [7]

Answer:

d = 52.20 miles

Explanation:

Given that,

Devon drove 50 miles west and then drove 15 miles north.

We need to find Devon's displacement. Let it is d. It can be calculated as follows :

d=\sqrt{50^2+15^2} \\\\=52.20\ \text{miles}

Hence, Devon's displacement is 52.20 miles.

4 0
3 years ago
Unpolarized light is passed through three successive Polaroid filters, each with its transmission axis at 45.0° to the preceding
allsm [11]

Answer:

The percentage is  k = 12.5 \%

Explanation:

From the question we are told that

    The  axis is is  at  \theta =  45 ^o

Generally the of intensity light emerging from the first polarizer is mathematically represented as

                I_{1} =  \frac{I_o}{ 2}

Where  I_o is the intensity of unpolarized light

       Now the light emerging from the second polarizer is mathematically represented as

         I_2  = I_ 1 * cos ^2(\theta )

         I_2  = \frac{I_o}{2}  * cos ^2(45 )

        I_2  = \frac{I_o}{2} *  \frac{1}{2}  =  \frac{I_o}{4}

  Now the light emerging from the third  polarizer is mathematically represented as      

       I_3  = I_ 2 * cos ^2(\theta )

       I_3  = \frac{I_o}{4}   * cos ^2(45 )

      I_3  = \frac{I_o}{8}

Now the percentage of the intensity of light that emerged with respect to the intensity of  the unpolarized light is

      k =  \frac{\frac{I_o}{8} }{I_o }  * 100

     k = 12.5 \%

       

3 0
3 years ago
Situation A bichromatic source produces light having wavelengths in vacuum of 450 nm and 650 nm. The indices of refraction are 1
erica [24]

Answer:

\theta=0.52^{\circ}

Explanation:

It is given that,

Wavelength in vacuum, \lambda_1=450\ nm

Wavelength in vacuum, \lambda_2=650\ nm

Refractive index for air, n_1=1

First refractive index, n =1.44

Second refractive index, n' =1.42

A ray is incident at an angle of incidence of 50 degrees. Let r is the angle of refraction. Firstly calculating the angle of refraction for two values of wavelength from Snell's law as :

\dfrac{sin\ i}{sin\ r}=\dfrac{n_2}{n_1}

r=sin^{-1}(\dfrac{n_1\ sin\ i}{n})

For 450 nm, r=sin^{-1}(\dfrac{1\ sin(50)}{1.44})

r = 32.13 degrees

For 650 nm, r'=sin^{-1}(\dfrac{1\ sin(50)}{1.42})

r' = 32.65 degrees

Let \theta is the angle of dispersion between the two refracted rays in the oil such that,

\theta=r'-r

\theta=32.65-32.13

\theta=0.52^{\circ}

So, the angle of dispersion between the two refracted rays in the oil is closest to 0.52 degrees.

3 0
3 years ago
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